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Electric use of z-wave devices; electric "cost" of polling?

Last post 02-08-2010 9:28 AM by kenny. 1 replies.
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  • 02-06-2010 11:32 AM

    • MrAndrew
    • Top 150 Contributor
    • Joined on 08-15-2009
    • Oakland, CA
    • Posts 7

    Electric use of z-wave devices; electric "cost" of polling?

    Hi All;

     

    I have recently finished a massive remodel on my home including 100% new wiring, switches, lights, thermostats, etc.  All the thermostats are WD-20's.  All the light switches are either Vizia+ or Vizia-RF+ (I couldn’t afford to do all the switches as RF - sigh.)

     

    I have:

    ·         WD-20 Thermostats: 7

    ·         Leviton Vizia-RF+ switches (various): 25

    ·         Leviton Vizia-RF+ 4-button controllers (scene or zone): 13

    ·         Leviton Vizia-RF+ 1-button controllers: 2

    ·         Non RF Vizia switches: 64

    ·         WD USB z-wave stick

     

    So, yes, I have a lot of lights, ceiling fans, and switches.  As it turns out, my electrical bills are astronomical L.  [On the other hand, I have a super-high-efficiency gas fired boiler, radiant heat, super-high-efficiency washer, dryer, dishwasher, fridge, etc,etc – go figure.]  I bought a couple “Kill-A-Watt” units to check the usage of plugged devices, but so far no smoking gun.  I have ordered a whole-house meter, but it hasn’t arrived yet.

     

    I was wondering if anyone has information on the electric usage of Z-wave devices. Since each switch or controller contains a z-wave chip – which is basically an embedded CPU plus a radio – they must use some power.  They are on 24/7/365 and are always listening even if they are not broadcasting. I have a Leviton RZCPG hand-held controller, but I’ve stopped using it because it eats through batteries so fast that it is just stupid – that leads me to believe that some measurable energy is being used. In addition, all of these devices have LEDs (even the non-RF switches.)  I’m sure the energy use of each LED is miniscule; however, we are talking 100 devices times 24/7/365.

     

    I scoured Leviton’s web site, but couldn’t find any info on the energy overhead of the switch itself.  Google-ing (Bing-ing???) for “z-wave energy use” (etc) turns up endless hits touting the energy savings of home automation, but nothing about the overhead incurred by the switches themselves.

     

    Finally, I was wondering about the cost incurred by ThinkEssentials polling.  I had set the polling rate to 1 minute. Since every poll is a system-wide broadcast that forces each of my 45 z-wave devices to wake up and start chatting, knowing the energy use of a poll could be helpful.  If the cost to poll one device (averaging out the hops and repeating that other devices will do) is, say 0.5 watt, that is 22.5 watts per poll (times some number of seconds), 1.35kw per hour for polling or almost 32kw per day.  Each poll takes some unknown number of seconds, so god knows what the Kwh turns out to be. Anyway, I have lowered the polling rate to 30 minutes – perhaps that will help my bills?

     

    Any information or insights would be appreciated.

     

    Andrew

     

     

     

     

     

     

     

  • 02-08-2010 9:28 AM In reply to

    • kenny
    • Top 75 Contributor
    • Joined on 11-16-2009
    • Posts 14

    Re: Electric use of z-wave devices; electric "cost" of polling?

    leviton zwave devices use less than 1 Watt. If you use kill-a-watt, you're probably not going to see anything. The zwave chip in each device will be in sleep mode if it's not used, which takes around 2.5uA on 3.3V DC. we're talking about micro-Watts.

    That math would look something like this, assuming 0.0005 KwH electricity usage.

    0.0005*24*365 = 4.38 KW/per year per device.

    you could just disable the polling from the thinkessentials and use the F5 key to refresh the status on the zwave devices, which acts as an on-demand polling function. It saves you a lot of RF traffics on the network.

    SE, Leviton
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